Difference between revisions of "User talk:Wheo001"
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Assume we have wave travelling with speed <math> V_0 </math> without change of form, | Assume we have wave travelling with speed <math> V_0 </math> without change of form, | ||
− | <center><math> H(z,tau)=H(z- | + | <center><math> H(z,tau)=H(z-V_0tau) </math></center> and substitue into KdV equation then we obtain |
<center><math> | <center><math> | ||
-2V_oH_xi+3HH_xi+frac{1}{3}H_xixixi=0</math></center> | -2V_oH_xi+3HH_xi+frac{1}{3}H_xixixi=0</math></center> | ||
− | where <math>xi=z- | + | where <math>xi=z-V_0tau </math> is the travelling wave coordinate. |
We integrate this equation twice with respect to <math> xi</math> to give | We integrate this equation twice with respect to <math> xi</math> to give | ||
<center><math> frac{1}{6}H_xi^2=V_oH^2-frac{1}{2}H^3+D_1H+D2=f(H,V_0,D_1,D_2) </math></center>, where D_1 and D_2 are constants of integration. | <center><math> frac{1}{6}H_xi^2=V_oH^2-frac{1}{2}H^3+D_1H+D2=f(H,V_0,D_1,D_2) </math></center>, where D_1 and D_2 are constants of integration. | ||
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It turns out that we require 3 real roots to obatain periodic solutions. | It turns out that we require 3 real roots to obatain periodic solutions. | ||
Let roots be <math> H_1 $leq H_2 $leq H_3</math>. | Let roots be <math> H_1 $leq H_2 $leq H_3</math>. | ||
− | We can imagine the graph of cubic function which has 3 real | + | We can imagine the graph of cubic function which has 3 real roots and we can now write a function |
+ | <center><math> f(H)= frac{-1}{2}(H-H_1)(H-H_2)(H-H_3)</math></center> |
Revision as of 01:55, 14 October 2008
Travelling Wave Solutions of the KdV Equation
The KdV equation has two qualitatively different types of permanent form travelling wave solution. These are referred to as cnoidal waves and solitary waves.
Introduction
Assume we have wave travelling with speed [math]\displaystyle{ V_0 }[/math] without change of form,
and substitue into KdV equation then we obtain
where [math]\displaystyle{ xi=z-V_0tau }[/math] is the travelling wave coordinate. We integrate this equation twice with respect to [math]\displaystyle{ xi }[/math] to give
, where D_1 and D_2 are constants of integration.
We define [math]\displaystyle{ f(H)= V_oH^2-frac{1}{2}H^3+D_1H+D2 }[/math], i.e [math]\displaystyle{ f(H)=frac{1}{6}H_xi^2. It turns out that we require 3 real roots to obatain periodic solutions. Let roots be \lt math\gt H_1 $leq H_2 $leq H_3 }[/math]. We can imagine the graph of cubic function which has 3 real roots and we can now write a function