Difference between revisions of "Template:Standard linear problem notation"

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We assume small amplitude so that we can linearise all the
 
We assume small amplitude so that we can linearise all the
equations (see [[Linear and Second-Order Wave Theory]]). We also assume that [[Frequency Domain Problem]] with frequency <math>\omega</math>
+
equations (see [[Linear and Second-Order Wave Theory]]).  
and we assume that all variables are proportional to
+
{{frequency definition}}
<center>
 
<math>\exp(i\omega t)\,</math>
 
</center>
 
 
The water motion is represented by a velocity potential which is
 
The water motion is represented by a velocity potential which is
 
denoted by <math>\phi\,</math>.  The coordinate system is the standard Cartesian coordinate system
 
denoted by <math>\phi\,</math>.  The coordinate system is the standard Cartesian coordinate system

Revision as of 09:05, 19 August 2009

We assume small amplitude so that we can linearise all the equations (see Linear and Second-Order Wave Theory). We also assume that Frequency Domain Problem with frequency [math]\displaystyle{ \omega }[/math] and we assume that all variables are proportional to [math]\displaystyle{ \exp(-\mathrm{i}\omega t)\, }[/math] The water motion is represented by a velocity potential which is denoted by [math]\displaystyle{ \phi\, }[/math]. The coordinate system is the standard Cartesian coordinate system with the [math]\displaystyle{ z- }[/math]axis pointing vertically up. The water surface is at [math]\displaystyle{ z=0 }[/math] and the region of interest is [math]\displaystyle{ -h\lt z\lt 0 }[/math]. There is a body which occupies the region [math]\displaystyle{ \Omega }[/math] and we denote the wetted surface of the body by [math]\displaystyle{ \partial\Omega }[/math] We denote [math]\displaystyle{ \mathbf{r}=(x,y) }[/math] as the horizontal coordinate in two or three dimensions respectively and the Cartesian system we denote by [math]\displaystyle{ \mathbf{x} }[/math]. We assume that the bottom surface is of constant depth at [math]\displaystyle{ z=-h }[/math].