Difference between revisions of "Template:Standard linear problem notation"
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We assume small amplitude so that we can linearise all the | We assume small amplitude so that we can linearise all the | ||
equations (see [[Linear and Second-Order Wave Theory]]). We also assume that [[Frequency Domain Problem]] with frequency <math>\omega</math> | equations (see [[Linear and Second-Order Wave Theory]]). We also assume that [[Frequency Domain Problem]] with frequency <math>\omega</math> | ||
+ | and we assume that all variables are proportional to | ||
+ | <center> | ||
+ | <math>\exp(i\omega t)</math> | ||
+ | </center> | ||
The water motion is represented by a velocity potential which is | The water motion is represented by a velocity potential which is | ||
denoted by <math>\phi</math>. The coordinate system is the standard Cartesian coordinate system | denoted by <math>\phi</math>. The coordinate system is the standard Cartesian coordinate system |
Revision as of 08:58, 13 September 2008
We assume small amplitude so that we can linearise all the equations (see Linear and Second-Order Wave Theory). We also assume that Frequency Domain Problem with frequency [math]\displaystyle{ \omega }[/math] and we assume that all variables are proportional to
[math]\displaystyle{ \exp(i\omega t) }[/math]
The water motion is represented by a velocity potential which is denoted by [math]\displaystyle{ \phi }[/math]. The coordinate system is the standard Cartesian coordinate system with the [math]\displaystyle{ z }[/math] axis pointing vertically up. The water surface is at [math]\displaystyle{ z=0 }[/math] and the region of interest is [math]\displaystyle{ -h\lt z\lt 0 }[/math]. There is a body which occupies the region [math]\displaystyle{ \Omega }[/math] and we denoted the wetted surface of the body by [math]\displaystyle{ \partial\Omega }[/math] We denote [math]\displaystyle{ \mathbf{r}=(x,y) }[/math] as the horizontal coordinate in two or three dimensions respectively and the cartesian system we denote by [math]\displaystyle{ \mathbf{x} }[/math]. We assume that the bottom surface is of constant depth at [math]\displaystyle{ z=-h }[/math].