Difference between revisions of "Nonlinear Shallow Water Waves"
From WikiWaves
Jump to navigationJump to search| Line 7: | Line 7: | ||
</math> | </math> | ||
| − | Since water is incompressible i.e. <math> \frac{D \rho}{D t} = 0 </math> and then <math>\nabla \cdot \vec{u} = 0</math> | + | Since water is incompressible i.e. <math> \frac{D \rho}{D t} = 0 </math> and then <math>\nabla \cdot \vec{u} = 0</math> i.e. the divergance of the velocity field is zero. |
[[Category:789]] | [[Category:789]] | ||
Revision as of 07:44, 14 October 2008
Introduction
We want to consider
[math]\displaystyle{ \frac{D \rho}{D t} (\vec{x} ,t) + \rho(\vec{x} ,t)\nabla \cdot u(\vec{x} ,t) = 0, x \in \Omega }[/math]
Since water is incompressible i.e. [math]\displaystyle{ \frac{D \rho}{D t} = 0 }[/math] and then [math]\displaystyle{ \nabla \cdot \vec{u} = 0 }[/math] i.e. the divergance of the velocity field is zero.
