Difference between revisions of "Method of Characteristics for Linear Equations"
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− | \frac{d U}{d t} = \partial_t u + \frac{d X}{dt}\partial_x u = \partial_x u \left(\frac{d X}{dt} | + | \frac{d U}{d t} = \partial_t u + \frac{d X}{dt}\partial_x u = \partial_x u \left(\frac{d X}{dt} - 1 \right) |
</math></center> | </math></center> | ||
+ | |||
+ | Therefore along the curve <math>\frac{d X}{dt} = 1</math> <math>u(x,t)</math> must be a constant. | ||
+ | These are nothing but the straight lines <math>x = t+c</math> | ||
+ | This means that we have | ||
+ | <center> | ||
+ | <math> | ||
+ | u(x,t) = u(-t+c,t) = u(c,0) = f(c) = f(x+t) | ||
+ | </math></center> | ||
+ | Therefore the solution is given |
Revision as of 04:30, 23 July 2010
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We present here a brief account of the method of characteristic for linear waves.
Introduction
The method of characteristics is an important method for hyperbolic PDE's which applies to both linear and nonlinear equations.
We begin with the simplest wave equation
subject to the initial conditions
We consider the solution along the curve [math]\displaystyle{ (x,t) = (X(t),t) }[/math]. We then have
Therefore along the curve [math]\displaystyle{ \frac{d X}{dt} = 1 }[/math] [math]\displaystyle{ u(x,t) }[/math] must be a constant. These are nothing but the straight lines [math]\displaystyle{ x = t+c }[/math] This means that we have
Therefore the solution is given