Difference between revisions of "Eigenfunction Matching for a Finite Change in Depth"

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=== Expansion of the potential ===
 
 
We need to apply some boundary conditions at plus and minus infinity,
 
where are essentially the the solution cannot grow. This means that we
 
only have the positive (or negative) roots of the dispersion equation.
 
However, it does not help us with the purely imaginary root. Here we
 
must use a different condition, essentially identifying one solution
 
as the incoming wave and the other as the outgoing wave.
 
 
Therefore the scattered potential (without the incident wave, which will
 
be added later) can
 
be expanded as
 
<center>
 
<math>
 
\phi(x,z)=\sum_{m=0}^{\infty}a_{m}e^{k_{m}^{h} x}\phi_{m}^{h}(z), \;\;x<0
 
</math>
 
</center>
 
and
 
<center>
 
<math>
 
\phi(x,z)=\sum_{m=0}^{\infty}b_{m}
 
e^{-k_{m}^{d}x}\phi_{m}^{d}(z), \;\;x>0
 
</math>
 
</center>
 
where <math>a_{m}</math> and <math>b_{m}</math>
 
are the coefficients of the potential in the left and right respectively
 
and <math>k_{m}^{h}</math> denotes the solution for depth <math>h</math> etc.
 
 
{{incident potential for two dimensions}}
 
  
 
=== Inner product between free surface and dock modes ===
 
=== Inner product between free surface and dock modes ===

Revision as of 22:56, 13 October 2010


Introduction

The problem consists of a region to the left with a free water surface with depth [math]\displaystyle{ d }[/math] and to the right a region of depth [math]\displaystyle{ h }[/math]. The problem with a semi-infinite change in depth is treated in Eigenfunction Matching for a Semi-Infinite Change in Depth

Governing Equations

We begin with the Frequency Domain Problem for a submerged dock which occupies the region [math]\displaystyle{ x\gt 0 }[/math] (we assume [math]\displaystyle{ e^{i\omega t} }[/math] time dependence). The depth of is constant [math]\displaystyle{ h }[/math] for [math]\displaystyle{ x\lt -L }[/math] and [math]\displaystyle{ x\gt L }[/math] and constant [math]\displaystyle{ d }[/math] for [math]\displaystyle{ -L\lt x\gt L }[/math]. The [math]\displaystyle{ z }[/math]-direction points vertically upward with the water surface at [math]\displaystyle{ z=0 }[/math]. The boundary value problem can therefore be expressed as

[math]\displaystyle{ \Delta\phi=0, \,\, -h\lt z\lt 0, \,\, x\lt -L\,\textrm{or}\, x\gt L, }[/math]
[math]\displaystyle{ \Delta\phi=0, \,\, -d\lt z\lt 0, \,\, -L\lt x\lt L, }[/math]
[math]\displaystyle{ \partial_z\phi=\alpha\phi, \,\, z=0, }[/math]
[math]\displaystyle{ \partial_x\phi=0, \,\, -d\lt z\lt -h,\,x=\pm{L}, }[/math]
[math]\displaystyle{ \partial_z\phi=0, \,\, z=-h,\, x\lt -L\,\textrm{or}\, x\gt L, }[/math]
[math]\displaystyle{ \partial_z\phi=0, \,\, z=-d,\, -L\lt x\lt L. }[/math]

We must also apply the Sommerfeld Radiation Condition as [math]\displaystyle{ |x|\rightarrow\infty }[/math]. This essentially implies that the only wave at infinity is propagating away and at negative infinity there is a unit incident wave and a wave propagating away.

Solution Method

We use separation of variables in the two regions, [math]\displaystyle{ x\lt 0 }[/math] and [math]\displaystyle{ x\gt 0 }[/math].

We express the potential as

[math]\displaystyle{ \phi(x,z) = X(x)Z(z)\, }[/math]

and then Laplace's equation becomes

[math]\displaystyle{ \frac{X^{\prime\prime}}{X} = - \frac{Z^{\prime\prime}}{Z} = k^2 }[/math]

Separation of variables for a free surface

We use separation of variables

We express the potential as

[math]\displaystyle{ \phi(x,z) = X(x)Z(z)\, }[/math]

and then Laplace's equation becomes

[math]\displaystyle{ \frac{X^{\prime\prime}}{X} = - \frac{Z^{\prime\prime}}{Z} = k^2 }[/math]

The separation of variables equation for deriving free surface eigenfunctions is as follows:

[math]\displaystyle{ Z^{\prime\prime} + k^2 Z =0. }[/math]

subject to the boundary conditions

[math]\displaystyle{ Z^{\prime}(-h) = 0 }[/math]

and

[math]\displaystyle{ Z^{\prime}(0) = \alpha Z(0) }[/math]

We can then use the boundary condition at [math]\displaystyle{ z=-h \, }[/math] to write

[math]\displaystyle{ Z = \frac{\cos k(z+h)}{\cos kh} }[/math]

where we have chosen the value of the coefficent so we have unit value at [math]\displaystyle{ z=0 }[/math]. The boundary condition at the free surface ([math]\displaystyle{ z=0 \, }[/math]) gives rise to:

[math]\displaystyle{ k\tan\left( kh\right) =-\alpha \, }[/math]

which is the Dispersion Relation for a Free Surface

The above equation is a transcendental equation. If we solve for all roots in the complex plane we find that the first root is a pair of imaginary roots. We denote the imaginary solutions of this equation by [math]\displaystyle{ k_{0}=\pm ik \, }[/math] and the positive real solutions by [math]\displaystyle{ k_{m} \, }[/math], [math]\displaystyle{ m\geq1 }[/math]. The [math]\displaystyle{ k \, }[/math] of the imaginary solution is the wavenumber. We put the imaginary roots back into the equation above and use the hyperbolic relations

[math]\displaystyle{ \cos ix = \cosh x, \quad \sin ix = i\sinh x, }[/math]

to arrive at the dispersion relation

[math]\displaystyle{ \alpha = k\tanh kh. }[/math]

We note that for a specified frequency [math]\displaystyle{ \omega \, }[/math] the equation determines the wavenumber [math]\displaystyle{ k \, }[/math].

Finally we define the function [math]\displaystyle{ Z(z) \, }[/math] as

[math]\displaystyle{ \chi_{m}\left( z\right) =\frac{\cos k_{m}(z+h)}{\cos k_{m}h},\quad m\geq0 }[/math]

as the vertical eigenfunction of the potential in the open water region. From Sturm-Liouville theory the vertical eigenfunctions are orthogonal. They can be normalised to be orthonormal, but this has no advantages for a numerical implementation. It can be shown that

[math]\displaystyle{ \int\nolimits_{-h}^{0}\chi_{m}(z)\chi_{n}(z) \mathrm{d} z=A_{n}\delta_{mn} }[/math]

where

[math]\displaystyle{ A_{n}=\frac{1}{2}\left( \frac{\cos k_{n}h\sin k_{n}h+k_{n}h}{k_{n}\cos ^{2}k_{n}h}\right). }[/math]

Solution using Symmetry

The finite dock problem is symmetric about the line [math]\displaystyle{ x=0 }[/math] and this allows us to solve the problem using symmetry. This method is numerically more efficient and requires only slight modification of the code for Eigenfunction Matching for a Semi-Infinite Dock, the developed theory here is very close to the semi-infinite solution. We decompose the solution into a symmetric and an anti-symmetric part as is described in Symmetry in Two Dimensions

Symmetric solution

The symmetric potential can be expanded as

[math]\displaystyle{ \phi(x,z)=e^{-k_{0}^{h}(x+L)}\phi_{0}\left( z\right) + \sum_{m=0}^{\infty}a_{m}^{s}e^{k_{m}^{h}(x+L)}\phi_{m}^{h}(z) , \;\;x\lt -L }[/math]

and

[math]\displaystyle{ \phi(x,z)=\sum_{m=0}^{\infty}b_{m}^{s} \frac{\cosh k_{m}^{d} x}{\cosh k_{m}^{d} L} \phi_{m}^{d}(z), \;\;-L\lt x\lt 0 }[/math]

where [math]\displaystyle{ a_{m}^{s} }[/math] and [math]\displaystyle{ b_{m}^{s} }[/math] are the coefficients of the potential in the two regions.

We now match at [math]\displaystyle{ x=-L }[/math] and multiply both equations by [math]\displaystyle{ \phi_{l}(z) }[/math] and integrating from [math]\displaystyle{ -h }[/math] to [math]\displaystyle{ 0 }[/math] to obtain:

[math]\displaystyle{ A_{0}\delta_{0l}+a_{l}^{s}A_{l} =\sum_{n=0}^{\infty}b_{m}^{s}B_{ml} }[/math]

and

[math]\displaystyle{ -k_{0}A_{0}\delta_{0l}+a_{l}^{s} k_{m}^{h} A_l =-\sum_{m=0}^{\infty}b_{m}^{s} k_{m}^{d}\tanh(k_{m}^{d} L) B_{ml} }[/math]

(for full details of this derivation see Eigenfunction Matching for a Semi-Infinite Change in Depth)

Anti-symmetric solution

The anti-symmetric potential can be expanded as

[math]\displaystyle{ \phi(x,z)=e^{-k_{m}^{h}(x+L)}\phi_{0}\left( z\right) + \sum_{m=0}^{\infty}a_{m}^{a}e^{k_{m}^{h}(x+L)}\phi_{m}(z) , \;\;x\lt -L }[/math]

and

[math]\displaystyle{ \phi(x,z)=\sum_{m=0}^{\infty}b_{m}^{a} \frac{\sinh k_{m}^{h} x}{-\sinh k_{m}^{h} L}\phi_{m}(z), \;\;-L\lt x\lt 0 }[/math]

where [math]\displaystyle{ a_{m}^{a} }[/math] and [math]\displaystyle{ b_{m}^{a} }[/math] are the coefficients of the potential in the two regions. Note that the minus sign in the expression for the dock-covered region has been added so that each component is equal to one at [math]\displaystyle{ x=-L }[/math].

We now match at [math]\displaystyle{ x=-L }[/math] and multiply both equations by [math]\displaystyle{ \phi_{l}(z) }[/math] and integrating from [math]\displaystyle{ -h }[/math] to [math]\displaystyle{ 0 }[/math] to obtain:

[math]\displaystyle{ A_{0}\delta_{0l}+a_{l}^{a}A_{l} =\sum_{n=0}^{\infty}b_{m}^{a}B_{ml} }[/math]

and

[math]\displaystyle{ -k_{0}A_{0}\delta_{0l}+a_{l}^{a}k_{l}^{h} A_l = - \frac{b_{0}^{a}}{L}B_{0l} -\sum_{m=1}^{\infty}b_{m}^{a}k_{m}^{d}\coth(k_{m}^{d}L) B_{ml} }[/math]

(for full details of this derivation see Eigenfunction Matching for a Semi-Infinite Change in Depth)

Solution to the original problem

We can now reconstruct the potential for the finite dock from the two previous symmetric and anti-symmetric solution as explained in Symmetry in Two Dimensions. The amplitude in the left open-water region is simply obtained by the superposition principle

[math]\displaystyle{ a_{m} = \frac{1}{2}\left(a_{m}^{s}+a_{m}^{a}\right) }[/math]

[math]\displaystyle{ d_{m} = \frac{1}{2}\left(a_{m}^{s}-a_{m}^{a}\right) }[/math]

Note the formulae for [math]\displaystyle{ b_m }[/math] and [math]\displaystyle{ c_m }[/math] are more complicated but can be derived with some work.


Inner product between free surface and dock modes

[math]\displaystyle{ B_{mn} = \int\nolimits_{-h}^{0}\phi_{m}^{d}(z)\phi_{n}^{h}(z) \mathrm{d} z }[/math]

where

[math]\displaystyle{ B_{mn}= \int\nolimits_{-h}^{0} \frac{\cos(k_{m}^{h}(z+h))\cos(k_{n}^{d}(z+d))}{\cos(k_{m}h)\cos(k_{n}d)} \mathrm{d} z =\frac{k_{m}^{h}\sin(k_{m}^{d} h)\cos(k_{n}^{d}h)-k_{n}^{d}\cos(k_{m}^{h} h)\sin(k_{n}^{d}h)} {\cos(k_{m}h)\cos(k_{n}d)({k_{m}^{d}}^{2}-{k_{n}^{d}}^{2})} }[/math]

Matlab Code

A program to calculate the coefficients for the semi-infinite dock problems can be found here semi_infinite_change_in_depth.m

Additional code

This program requires